Proposition I.2 · Problem
To place at a given point a straight line equal to a given straight line.
Drag the points circled in red. The figure changes, and every step of the proof still holds.
- Let A be the given point, and BC the given straight line. It is required to place at the point A a straight line equal to BC.
- From the point A to the point B let the straight line AB be joined.Postulate 1Postulate 1: To draw a straight line from any point to any point.
- On AB let the equilateral triangle DAB be constructed.Proposition I.1Proposition I.1: On a given finite straight line to construct an equilateral triangle.
- Let the straight lines AE, BF be produced in a straight line with DA, DB.Postulate 2Postulate 2: To produce a finite straight line continuously in a straight line.
- With centre B and distance BC let the circle CGH be described; it meets BF at G.Postulate 3Postulate 3: To describe a circle with any centre and distance.
- Again, with centre D and distance DG let the circle GKL be described; it meets AE at L.Postulate 3Postulate 3: To describe a circle with any centre and distance.
- Since the point B is the centre of the circle CGH, BC is equal to BG.Definition 15Definition 15: A circle is a plane figure contained by one line such that all the straight lines falling upon it from one point among those lying within the figure are equal to one another.
- Again, since the point D is the centre of the circle GKL, DL is equal to DG.Definition 15Definition 15: A circle is a plane figure contained by one line such that all the straight lines falling upon it from one point among those lying within the figure are equal to one another.
- And in these DA is equal to DB; subtracting DA, DB from the equals DL, DG, the remainder AL is equal to the remainder BG.Common Notion 3Common Notion 3: If equals be subtracted from equals, the remainders are equal.
- But BC was also proved equal to BG; therefore each of the straight lines AL, BC is equal to BG. Things which are equal to the same thing are also equal to one another; therefore AL is also equal to BC. So at the given point A the straight line AL has been placed equal to the given straight line BC.Common Notion 1Common Notion 1: Things which are equal to the same thing are also equal to one another.
Being what it was required to do.